3b^2-18b+20=5

Solution for 3b^2-18b+20=5 equation:

Simplifying
3b2 + -18b + 20 = 5

Reorder the terms:
20 + -18b + 3b2 = 5

Solving
20 + -18b + 3b2 = 5

Solving for variable 'b'.

Reorder the terms:
20 + -5 + -18b + 3b2 = 5 + -5

Combine like terms: 20 + -5 = 15
15 + -18b + 3b2 = 5 + -5

Combine like terms: 5 + -5 = 0
15 + -18b + 3b2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(5 + -6b + b2) = 0

Factor a trinomial.
3((1 + -1b)(5 + -1b)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {1, 5}